52. Решение задачи по химии №79

2. The heat of the reaction Pb Hg2Cl2 = PbCl2 2 Hg is 22710 cal at 298 K. The EMF of the element operating due to this reaction increases by 0.000145 V with an increase in temperature by 10. Determine the EMF of the element and the change in entropy of the reaction at 298 K.

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