30. Решение задачки по химии №7

2. The EMF of the element in which the reaction Cd PbCl2 2.5H2O=CdCl2*2.5H2O Pb occurs is 0.188 V at 298.2 K: dE/dT=-4.8*104 V/K. Calculate the change in thermodynamic functions: ΔG0298, ΔH0298, ΔS0298. Make an electrochemical circuit and write the equations of potential-determining reactions on the electrodes.

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