9. Решение задачки по химии №312

2. The EMF of the element in which the reaction Pb 2AgCl↔PbCl2 2Ag occurs is 0.2107 V at 298.2 K dE/dT=-1.38*10-4 V/K. Calculate the change in thermodynamic functions: ΔG0298, ΔH0298, ΔS0298. Draw up an electrochemical circuit and write the equations of potential-determining reactions on the electrodes.

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