5. Решение задачки по химии №26

4. The EMF of the Pt element, H2/Pt, (p=1)H2/H2SO4/Hg2SO4solid,Hg is 0.7540 V, and if p(H₂) = 0.5 atm, and p(H2SO4) = 0.5, sulfuric acid at pH=0.05 is 0.340. Determine the EMF of the acid at pH=0.5 without using the table of standard potentials.

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