31. Решение задачки по химии №02121566

3. The molar light absorption coefficients of monoethanolamine at 785 and 728 cm-1 are: ε785 = 1.67 and ε728 = 0.0932, and for diethanolamine - ε785 = 0.0446 and ε728 = 1.17. Calculate the concentration (mol/l) of mono- and diethanolamine in the mixture if the optical density values measured under the same conditions at l = 1 cm are equal to: A785 = 0.525; A728 = 0.715.

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