31. Решение задачки по химии №0288

71. For the anaerobic type of nutrition process C6H12O6 = 2C2H5OH 2CO2 ΔG0 = -243.63 kJ/mol, and for the aerobic type of nutrition C6H12O6 6O2 = 6CO2 6H2O ΔG0 = -2872.3 kJ/mol. Which process is the most efficient in terms of the use of α-D-glucose?

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