32. Решение задачки по химии №125178

4. (3) During the electrolysis of a solution of lead nitrate, m(PbO2) g were released at the anode. Determine the molar concentration of the equivalent of Pb(N03)2 (feq = 1/2), if V ml of this solution was taken for analysis:
Option 3
V, ml 40.00
m (Pb02), g 0.2136

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