Задача id15334

If s is the surface charge density, and R is the radius of curvature of the charged surface at a given point, then the relation s ~ 1/R shows that the charge distributed on an insulated conductor is concentrated on the tips and avoids flat surfaces, where R -> oo. How can this be reconciled with the case shown in Figure 1, where the negative charge is distributed on the flat surface of each plate?

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