Задача id13759

The leading line of the Balmer series in the emission of atomic hydrogen, i.e. the line corresponding to the transition of an atom to a state with quantum number n = n1 = 2 from the nearest state with n = n1 + 1 = 3 has a wavelength l1 = 6.56 • 10-7 m. A series of radiation of the same atomic hydrogen with a wavelength of the head line l2 = 48.8 cm. Determine the corresponding quantum number of the final state of the atom n2 (take into account that n2 > 1).

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