34. Решение задачки по химии №088

EMF of the cell Pt ( t ) | Pb(t) | PbI2 (s) | HI ( aq ) |H2 (g)|Pt(t)
equal to 317.85 mV at 25 °C, hydrogen fugacity 125 kPa and molality HI 0.50 mol/kg. Calculate the activity coefficient HI (aq), knowing the standard emf of 365.00 mV at p (-) = 100 kPa.

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