08. Решение задачи по химии29
10. EMF of a cell from a lead anode in a 2.0 * 10-3 M KBr solution with pH 8.00 saturated with PbOHBr, and SVE is 0.303 V. Schematically draw the cell and calculate Ks PbOHBr. Answer: 2.0*10-15
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