50. Решение задачи по химии №005 026

290. To V (ml) of a 0.05 N solution of Me (NO3) 2 salt (feqv = ½) was added m (g) of the cation exchanger in the H-form. After equilibrium was established, the salt concentration decreased to c΄. Determine the static exchange capacity (mmol / g) of the cation exchanger, taking the molar mass of the equivalent M (1/2 Me2):
Task No. V, ml Me2 m, g s΄, mol/l
290 70 Ni 4.5 0.007

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