76 Решение задачки по химии №07 647

170. Calculate the change in entropy for reactions proceeding according to the equations, and explain the sign of the change in entropy:
a) 4HCl(g) O2(g) = 2H2O(g) 2Cl2(g);
b) C (graphite) H2O (g) \u003d CO (g) H2 (g).
Answer: a) -366.33 J/K; b) 133.6 J/K

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