76 Решение задачки по химии №07 647

161. Calculate the change in entropy for reactions proceeding according to the equations: a) CO2 (g) 4H2 (g) \u003d CH4 (g) 2H2O (g); b) CO(g) 3H2(g) = CH4(g) H2O(g). Explain the sign of entropy change.
Answer: a) -172.33 J/K; b) –214.27 J/K.

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