76 Решение задачки по химии №07 647

150. Based on the thermochemical equations of reactions:
1) KClO3 → KCl 1.5O2; ∆Н0298=-49.4 kJ;
2) KClO4 → KCl 2O2; ∆Н0298=33 kJ.
calculate ∆Н0298 of the reaction 4KClO3 → 3KClO4 KCl.
Answer: -296.6 kJ.

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