77 Решение задачки по химии №07 751

4. Calculate the enthalpy of the reaction under standard conditions С2Н6(g) 7/2 O2(g) ↔ 2СO2-(g) 3Н2O (g); ∆Nob(H2O)=-241.8 kJ/mol; ∆Nob(CO2)=-393.5 kJ/mol; ∆Nob(C2H6) = -89.7 kJ/mol.

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