87 Решение задачки по химии №08 790

620. Based on known electrode potentials at 25 °C:
Zn2 2 = Zn ε°=-0.763 V
Zn(CN)42- 2 = Zn 4CN- ε°=-1.26 V
calculate the Gibbs energy and the equilibrium constant of complex formation in an aqueous medium Zn2 4CN- = Zn(CN)42-.

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