120. Задачка по химии №012 061

29. A 10 ml alcohol solution of ethyl acetate was diluted to 100 ml. An aliquot of the solution, 20 ml in volume, was boiled in a flask under reflux with 40 ml of a 0.0546 M KOH solution:
CH3COOC2H5 OH- = CH3COO- C2H5OH
After cooling, the excess alkali was titrated with 12.43 ml of 0.0467 M HCl solution. What mass of ethyl acetate was contained in 100 ml of the initial solution?

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