121. Задачка по химии №012 138

14. Determine the activity of cadmium ions in a 0.025 M solution of K2CdI4, if the emf of the element
(-)Cd | K2CdI4 aq || KCl aq |Hg2Cl2,Hg ( )
C=0.025M C=0.1M
at 290 K is 0.824 V. The potential of the decinormal calomel electrode is
0.336V; the standard potential of the cadmium electrode with the activity of Cd2 ions equal to unity is 0.395 V.

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