124. Задачка по химии №012 466

9. Calculate the change in entropy upon cooling 50 g of benzene from 320 K to 200 K. Molar heat of crystallization Δ Hcr = -9843 J/mol; Тmelt = 279 K; Срж = 59.5 J/molK; Wed (tv) \u003d 73.24 J / mol * K.
Answer: ΔS = -43.47 J/K.
Define the third law of thermodynamics. How does the entropy of a substance change in the processes of evaporation, crystallization, and heating?

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.