Решение задачи по физике раздел 67 пункт 4 механика

4. A thin homogeneous rod AB of mass m = 1.0 kg moves progressively with acceleration a = 2.0 m / s2 under the action of two forces F1 and F2. The distance between the points of application of these forces is b = 20 cm. In addition, it is known that F2 = 5.0 N. Find the length of the rod.

Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)