Решение задачи по физике раздел 66 пункт 47 молекулярн

47. A certain gas with a substance quantity ν = 2 mol adiabatically expands into a vacuum from V1 = 10–3 m3 to V2 = 10−2 m3. Determine how many degrees of freedom this gas has if, during expansion, the gas temperature decreases by ΔT = 11.8 K. The Van der Waals correction a is assumed to be 0.136 N • m4 / mol2.

Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)