Задача 60505.

Confirm that during the nuclear reaction 14N7 + 1n0 = 14C6 + 1H1, 0.624 MeV will be released.

Detailed solution with a brief record of the conditions, formulas and laws used in the decision, the withdrawal of the calculation formula and the answer.
If you have any questions about the decision, write. I will try to help.