Вариант 29 ИДЗ 3.2

DHS - 3.2
№1.29. Vertices ∆АВС are given: А (–5; 1); B (8; –2); C (1; 4). Find: a) Equation side AB; b) Equation of height CH; c) the median AM equation; d) the intersection point N of the median AM and the height of the SN; e) the equation of a straight line passing through the vertex C and parallel to the side AB; f) distance from point C to straight line AB.
№2.29. Given the equation of the heights of the triangle ABC: 2x - 3y + 1 = 0; x + 2y + 1 = 0 and the coordinates of its vertex A (2; 3). Find the equations of sides AB and AC of a triangle.