Задача 40877.

The light beam propagating in the air at a frequency of 6 x 10 14 Hz is divided into two beams. Specify the result of the addition of these rays, when the first of them is the path of 4.5 mm in a medium with a dielectric constant e = 4, and the second - 8.5 micrometers in the air.

Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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