Задача 40864.

The steel rod cross-section of 10 cm ^ 2 applies a longitudinal wave. The equation of the end section of the rod oscillations has the form x = 8 * cos 10 ^ 3 * t m. Young´s modulus steel 2 x 10 6 kgf / cm ^ 2, the density of 8 g / cm ^ 3. Write the equation of the waves; determine a wavelength; the maximum value of the volumetric energy density in the rod.

Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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