Задача 40857.

The equation of a plane wave propagating in the rod cross-section of 10 cm ^ 2 has the form: s = 6 * 10 ^ 6 * cos (1900t-5,7x), m: determine the frequency of oscillation,. wavelength; wave propagation velocity in the rod. What kind of energy wave moves through the rod cross-section of 2? The density of the material of the rod 4 * 10 ^ 3 kg / m ^ 3.

Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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