Решение задачи по физике раздел 51 пункт 77 оптика

77. Determine the smallest thickness of the crystal plate at half wavelength for λ = 589 nm. if the difference in the refractive indices of the ordinary and extraordinary rays for a given wavelength n0 - ne = 0,17

Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)