Задача 20306.

Diatomic gas at a pressure of 440 kPa p1 = volume has V1 = 0,83 m ^ 3, at a pressure p2 = 120 kPa - volume V2 = 0,39 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. The amount of heat absorbed by the gas, Q, gas work A. Determine the increment of internal energy.

Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.

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