Задача 10278.

Normal acceleration point, moving in a circle R = 4 m, is given by: a = 1 + 6t + 9t2 (m / s ^ 2). Define: tangential acceleration point, the path traversed by a point in time after the start of movement 5s full acceleration for the time t = 1 s.

Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.

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